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Volumes of Gases.
Hydrogen is produced in the laboratory
by adding zinc to dilute
sulfuric
acid.
Example 3.
What volume of hydrogen is
produced
by reacting 6·5
g of zinc with dilute sulfuric
acid?
Method.
1) Find how many
moles of zinc are present
in 6·5 g of zinc.
RAM of
Zn = 65.
moles = mass ÷ RAM
moles
= 6·5 ÷ 65
= 0·1 moles of zinc.
2) Write the equation for the reaction.
zinc +
sulfuric acid zinc sulfate + hydrogen.
Zn(s) + H2SO4(aq) ZnSO4(aq)
+ H2(g)
Use the big numbers to find the proportion of reactant to product.
1Zn
makes 1H2, the proportion is 1 to 1,
so 0·1 moles of zinc will
make 0·1 moles of hydrogen.
volume = moles x 24,000 cm3
volume = 0·1 x
24,000 cm3
= 2,400 cm3 of hydrogen.
So, reacting 6·5 g of zinc with dilute
sulfuric acid
will produce
2,400 cm3 of hydrogen.
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